Star Trek – The Next Generation 

Union Rule : Moral Support and making contributions beyond the emotional or psychological value of encouragement.

An allegorical image depicting the human heart subjected to the seven deadly sins. The toad = avarice.

Leaps and Bounds Playplace slogan says ‘Play with Purpose’

Test Your Understanding

Problem 1

A pond contains 6 red jumping frogs and 4 black jumping frogs. Two frogs are drawn with replacement from the pond. What is the probability that both of the frogs are black?

(A) 0.16

(B) 0.32

(C) 0.36

(D) 0.40

(E) 0.60


The correct answer is A. Let A = the event that the first frog is black; and let B = the event that the second frog is black. We know the following:

* In the beginning, there are 10 frogs in the pond, 4 of which are black. Therefore, P(A) = 4/10.

* After the first selection, we replace the selected frog; so there are still 10 frogs in the pond, 4 of which are black. Therefore, P(B|A) = 4/10.

Therefore, based on the rule of multiplication:

P(A ∩ B) = P(A) P(B|A)

P(A ∩ B) = (4/10)*(4/10) = 16/100 = 0.16

Problem 2

A card is drawn randomly from a deck of ordinary players. You win $10 if the card is a spade or an ace. What is the probability that you will win the game?

(A) 1/13

(B) 13/52

(C) 4/13

(D) 17/52

(E) None of the above.


The correct answer is C. Let S = the event that the card is a spade; and let A = the event that the card is an ace. We know the following:

* There are 52 cards in the deck.

* There are 13 spades, so P(S) = 13/52.

* There are 4 aces, so P(A) = 4/52.

* There is 1 ace that is also a spade, so P(S ∩ A) = 1/52.

Therefore, based on the rule of addition:

P(S ∪ A) = P(S) + P(A) – P(S ∩ A)

P(S ∪ A) = 13/52 + 4/52 – 1/52 = 16/52 = 4/13

54 – but that depends on how many jokers are playing

T Says 53 cards so 1 Joker

Ask the proverbial question of why did the chosen people build a calf ?

To which one must understand Dear Jack

∴ The Answer is ?

Now confirmed to be 52 cards by the Fluffy one 🦁

In probability theory, events E1, E2, …, En are said to be mutually exclusive if the occurrence of any one of them implies the non-occurrence of the remaining n − 1 events. Therefore, two mutually exclusive events cannot both occur. Formally said, the intersection of each two of them is empty (the null event): A ∩ B = ∅. In consequence, mutually exclusive events have the property: P(A ∩ B) = 0.

For example, it is impossible to draw a card that is both red and a club because clubs are always black. If just one card is drawn from the deck, either a red card (heart or diamond) or a black card (club or spade) will be drawn. When A and B are mutually exclusive, P(A ∪ B) = P(A) + P(B). To find the probability of drawing a red card or a club, for example, add together the probability of drawing a red card and the probability of drawing a club. In a standard 52-card deck, there are twenty-six red cards and thirteen clubs: 26/52 + 13/52 = 39/52 or 3/4.

One would have to draw at least two cards in order to draw both a red card and a club. The probability of doing so in two draws depends on whether the first card drawn were replaced before the second drawing, since without replacement there is one fewer card after the first card was drawn. The probabilities of the individual events (red, and club) are multiplied rather than added. The probability of drawing a red and a club in two drawings without replacement is then 26/52 × 13/51 × 2 = 676/2652, or 13/51. With replacement, the probability would be 26/52 × 13/52 × 2 = 676/2704, or 13/52.

In probability theory, the word or allows for the possibility of both events happening. The probability of one or both events occurring is denoted P(A ∪ B) and in general it equals P(A) + P(B) – P(A ∩ B). Therefore, in the case of drawing a red card or a king, drawing any of a red king, a red non-king, or a black king is considered a success. In a standard 52-card deck, there are twenty-six red cards and four kings, two of which are red, so the probability of drawing a red or a king is 26/52 + 4/52 – 2/52 = 28/52.

Events are collectively exhaustive if all the possibilities for outcomes are exhausted by those possible events, so at least one of those outcomes must occur. The probability that at least one of the events will occur is equal to one. For example, there are theoretically only two possibilities for flipping a coin. Flipping a head and flipping a tail are collectively exhaustive events, and there is a probability of one of flipping either a head or a tail. Events can be both mutually exclusive and collectively exhaustive. In the case of flipping a coin, flipping a head and flipping a tail are also mutually exclusive events. Both outcomes cannot occur for a single trial (i.e., when a coin is flipped only once). The probability of flipping a head and the probability of flipping a tail can be added to yield a probability of 1: 1/2 + 1/2 =1.


A woman searches for a lost coin, finds it, and rejoices.
Joel’s theory explains the urgency of the woman’s search, and the extent of her joy when the missing coin is found. Can you relate how the woman in the parable felt when she found that one coin?

The invitation to friends and neighbors may reflect a celebratory meal when one understands what is value.

However for the sake of argument on value

What is the value of drachma these days? What is going to be the value of an old Rs 500 note ?

Hyperloop for connectivity

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Validated By Champion

Buy and Sell Handmade on

The Crocodile King 👑 is now THE NEW KING ALLIGATOR Crumong

Buy here : GMarket

Breaking from the virtuous vicious cycle of haters hate, and people are gonna die and you can go your own way to we care. Because a Gangster’s Paradise fails to see.

In statistics and regression analysis, an independent variable that can take on only two possible values is called a dummy variable. For example, it may take on the value 0 if an observation is of a male subject or 1 if the observation is of a female subject. The two possible categories associated with the two possible values are mutually exclusive, so that no observation falls into more than one category, and the categories are exhaustive, so that every observation falls into some category. Sometimes there are three or more possible categories, which are pairwise mutually exclusive and are collectively exhaustive — for example, under 18 years of age, 18 to 64 years of age, and age 65 or above. In this case a set of dummy variables is constructed, each dummy variable having two mutually exclusive and jointly exhaustive categories — in this example, one dummy variable (called D1) would equal 1 if age is less than 18, and would equal 0 otherwise; a second dummy variable (called D2) would equal 1 if age is in the range 18-64, and 0 otherwise. In this set-up, the dummy variable pairs (D1, D2) can have the values (1,0) (under 18), (0,1) (between 18 and 64), or (0,0) (65 or older) (but not (1,1), which would nonsensically imply that an observed subject is both under 18 and between 18 and 64). Then the dummy variables can be included as independent (explanatory) variables in a regression. Note that the number of dummy variables is always one less than the number of categories: with the two categories male and female there is a single dummy variable to distinguish them, while with the three age categories two dummy variables are needed to distinguish them.

Such qualitative data can also be used for dependent variables. For example, a researcher might want to predict whether someone goes to college or not, using family income, a gender dummy variable, and so forth as explanatory variables. Here the variable to be explained is a dummy variable that equals 0 if the observed subject does not go to college and equals 1 if the subject does go to college. In such a situation, ordinary least squares (the basic regression technique) is widely seen as inadequate; instead probit regression or logistic regression is used. Further, sometimes there are three or more categories for the dependent variable — for example, no college, community college, and four-year college. In this case, the multinomial probit or multinomial logit technique is used.

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See Also :

Reads and References :

Footnotes :

  • Therefore Sign : In mathematical proof, the therefore sign (∴) is generally used before a logical consequence, such as the conclusion of a syllogism. The symbol consists of three dots placed in an upright triangle and is read therefore.


(CC) 2016 Tysilyn Fernandez


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